The algorithm for calculating the value of the function F(n), where n – natural number, given by the following relations:
F(n) = 0 if n <= 0;
F(n) = F(n / 3) + n if 0 < n <= 100, and the number n is a multiple of 3;
F(n) = F(n - 1) + n if 0 < n <= 100 and n is not a multiple of 3;
F(n) = F(n - 3) if n > 100.
With how many different values n, in the range [100, 250], the result F(n) will be equal to 266?